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### Calculo Integral

Sea $$G(x) = 10x^9 + 1$$ Entonces $$\int_1^t{G(x)dx} =$$ $$= \int_1^t{(10x^9 + 1 )dx} =$$ $$= \left[x^{10}+x \right]_1^t =$$ $$= t^{10}+t -1 -1 =$$ $$= t^{10}+t -2$$ $$G(-1) = 10\cdot (-1)^9 +1 = -10+1 = -9$$